Worm/Win32.Runouce.b[Email]的网络行为
协议：TCP
端口：139 445
描述：通过以上端口发送恶意邮件，邮件内容：
HELO btamail.net.cn
MAIL FROM: imissyou@btamail.net.cn
RCPT TO:
DATA
TO:
SUBJECT: A-738DF22C9CA04 is comming!
MIME-Version: 1.0
--#BOUNDARY#
Content-Type: text/html
--#BOUNDARY#
MIME-Version: 1.0
Content-Type: audio/x-wav; name=pp.exe
Content-id: THE-CID
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经解密得到数据： HELO btamail.net.cn
MAIL FROM: imissyou@btamail.net.cn
RCPT TO:
DATA
FROM: A-738DF22C9CA04@yahoo.com
TO:
SUBJECT: A-738DF22C9CA04 is comming!
MIME-Version: 1.0
Content-type: multipart/mixed; boundary=#BOUNDARY#
--#BOUNDARY#
Content-Type: text/html
Content-Transfer-Encoding: quoted-printable
--#BOUNDARY#
MIME-Version: 1.0
Content-Type: audio/x-wav; name=pp.exe
Content-Transfer-Encoding: base64
Content-id: THE-CID
MZP ?@ ????L?悙This program must be run under Win32 $7PEL ?饨巵 D @ ` 0N@ CODE `DATA @?idata 0 @?reloc?@? @?%00@(08000F0F0KERNEL32.dllSleep 0`桄 媡$ ?ah @瞄Y? 佹???f?MZu?穨¬???L?悙This program must be run under Win32 $7圥E L ?饨 巵 @ P 0 N @ SCODE `DATA @ ?idata 0 @ ?reloc @ @ P???%00@??0 80 00 F0 F0 KERNEL32.dll Sleep? 0???G 缨 P嬆j PS?8X腱 ?G?QP嬆j PS?8XY怦胝瞄侅 3鰦黤? ??f?鲳???釆 B?纔麒 发送消息?企觲Xj?缨W嬝?樎褀Xj S?缨B嬝??褀_侅 Th j S?伳 纔 Th j S?F冩u 伳 陕 ?B$?Xh??镼??葖] 侅 孅?Runonce^h ?骢nyXTWjjVS?X??nyXjjj jS??A鑞yXh Wj jVS?胙槿?璱鑧X? jh?¬?缨,嬝?存wXj??Y兞 悙愯 *u鑧Xj Q?陕 槿`P L$?兝 ?婸 ?`?埘 ??销ff廆 媢 媫 婱 帖a陕 槿`婨 jPPj?恒陕
解密之后发现该内容为PE可执行文件，病毒调用系统自带的Outlook Express发送恶意邮件，病毒利用发送恶意邮件来传播自身。
注：%System32%是一个可变路径。病毒通过查询操作系统来决定当前System文件夹的位置。
%Windir% WINDODWS所在目录
%DriveLetter% 逻辑驱动器根目录
%ProgramFiles% 系统程序默认安装目录
%HomeDrive% 当前启动的系统的所在分区
%Documents and Settings% 当前用户文档根目录
%Temp% Documents and Settings当前用户Local SettingsTemp
%System32% 系统的 System32文件夹
Windows2000/NT中默认的安装路径是C:WinntSystem32
windows95/98/me中默认的安装路径是%WINDOWS%System
windowsXP中默认的安装路径是%system32%
请高手指点下,这个代码怎么解,我怎么解出来后还是乱码呀
这应该是双方规定的吧，要用同样的协议才可以解，你可以问问给你的发送方
求可用eset nod32用户名、密码(有效期长点的),或者激活码更好!_百度...
前面是用户：EAV-17255996
后面是密码：vb7cp2bd7v 不要加空格
EAV-17255996 - vb7cp2bd7v >> ess
EAV-17255997 - j6x7r7b7ff >> ess
EAV-17255998 - 7xp3rdb2r4 >> ess
EAV-17255999 - cfxbvc2fem >> ess
EAV-17256001 - n5hxxs242s >> ess
EAV-16888318 - ftj3phhbxx >> ess
EAV-16984825 - rn5a6rkvht >> ess
EAV-17221857 - curda2jaj4 >> ess
EAV-17221858 - 2nh8a7j4tm >> ess
EAV-17221853 - r7p7vn7nmr >> ess
EAV-17221854 - vpxf4mu7bb >> ess
EAV-17221855 - jjrb4tu2kv >> ess
EAV-17221856 - 7ch553usuf >> ess
EAV-16705393 - 3xxcramkjh >> ess
EAV-17139227 - 366k5k7per >> ess
EAV-17139236 - uaxusfxpkx >> ess
EAV-17167267 - 6crpe87h44 >> ess
电脑的防火墙什么的好用?
运行以后并合理的设置后才会有作用
建议用“天网防火墙”
天网功能齐全，设置简单，而且可以免费升级
最重要的是他的安全评测在国内防火墙中是最好的
这都是其他防火墙所不具备的
同构体素划分
设A与B分别为嵌套于Rm与Rn空间的k维流形实体，P(A)与P(B)分别为A与B的体素划分，如果P(A)与P(B)中相同维数的体素个数对应相等，则称P(A)与P(B)是同构体素划分。并且，存在k+1个一一映射，使得P(A)中的体素与P(B)中的体素一一对应。
如图2.8中，A、B与C分别为R1、R2与R3空间的一维流形实体，P(A)、P(B)与P(C)分别为A、B与C的体素划分，其中:
P(A)={(VA1，VA2，VA3，VA4)，(EA1，EA2，EA3)};
P(B)={(VB1，VB2，VB3，VB4)，(EB1，EB2，EB3)};
P(C)={(VC1，VC2，VC3，VC4)，(EC1，EC2，EC3)}。
按照上述定义，P(A)、P(B)与P(C)为同构体素划分。
图2.8所示的实例中，尽管A、B与C的形状不同，所在空间的维数也不同，但是，它们具有相同的结构，可以采用相同的方式表达流形实体内的体素及其相关关系。同构体素划分为我们表达复杂流形实体提供了有效方法，也就是说，我们可以根据同构的特性，利用抽象的流形实体表达所有结构相同的流形实体的拓扑。这种表示方法称为抽象拓扑表示。
图2.8 同构体素划分